File:Vapor pressure difference ice supercooled water.svg
Summary
| Description |
English: Difference of the saturation pressure of water vapor with respect to ice and supercooled liquid water, in the range of -50°C to 0°C. |
| Date | |
| Source |
Own work Formulae (7) and (10) from D. M. Murphy and T. Koop: "Review of the vapour pressures of ice and supercooled water for atmospheric applications", Q. J. R. Meteorol. Soc. 131 (2005), pp. 1539–1565, doi:10.1256/qj.04.94 |
| Author | Földhegy |
| Other versions |
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| SVG development | |
| Source code | Python codeimport numpy as np
import matplotlib.pyplot as plt
# Vapor pressure of ice and supercooled water (Temperature T in K)
def p_ice(T):
return np.exp(9.550426-5723.265/T+3.53068*np.log(T)-0.00728332*T)
def p_liq(T):
ln_p_liq=54.842763-6763.22/T-4.210*np.log(T)+0.000367*T+np.tanh(0.0415*(T-218.8))*(53.878-1331.22/T-9.44523*np.log(T)+0.014025*T)
return np.exp(ln_p_liq)
T1=-50
T2=0
ls=np.linspace(T1,T2,500)
fig,ax=plt.subplots(figsize=(7,4))
ax.plot(ls,p_ice(ls+273.15)-p_liq(ls+273.15),'C9-',label=r'$p_{ice}-p_{liquid}$')
ax.legend(loc='lower left')
ax.minorticks_on()
ax.grid(alpha=0.3)
ax.set(xlim=(T1,T2))
ax.set_ylabel('Partial pressure of water vapor [Pa]',fontsize=12)
ax.set_xlabel('Temperature [°C]',fontsize=12)
fig.savefig('Vapor_pressure_difference_ice_supercooled_water.svg', format='svg', bbox_inches='tight')
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