File:FFT py.png
Summary
| Description |
English: The first case relates to the smaller than signal length number of FFT points; the second - equal; the last - larger. |
| Date | |
| Source | Own work |
| Author | Kirlf |
| PNG development | |
| Source code | Python codeimport numpy as np
from scipy import signal
import matplotlib.pyplot as plt
Nsub = 100 # number of subsequences
w_1 = 20 # frequency of the 1st component of the signal (Hz)
w_2 = 40 # frequency of the 2nd component of the signal (Hz)
a = 1.1 # magnitude of the 1st component of the signal
b = 0.6 # magnitude of the 2nd component of the signal
t = np.array([i for i in range(1,301)])/1000 # time samples (s)
fs = 1 / (t[1]-t[0]) # sampling frequency (Hz)
x = a*np.cos(2*np.pi*w_1*t) + b*np.sin(2*np.pi*w_2*t) # considered signal
N = [len(x)-10, len(x), len(x)+10]
fig, ax = plt.subplots(len(N), 1, constrained_layout=True,\
figsize=(6, 7), dpi=250)
for idx, item in enumerate(N):
FFT = np.fft.fft(x, n=item)
amps = np.abs(FFT) / (len(FFT) / 2)
ax[idx].stem(f[:20], amps[:20])
ax[idx].grid(True)
ax[idx].set_ylabel('Magnitude of the FFT')
plt.xlabel('Frequencies (Hz)')
plt.show()
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